If the fire pump rotation is doubled, what will happen to the pressure?

When we consider the relationship between the rotational speed of a fire pump and the resulting pressure it generates, it is essential to understand how pressure changes with speed in fluid dynamics. The pressure generated by a pump is related to the square of the rotational speed. Therefore, if the rotational speed of the fire pump is doubled, the pressure produced by the pump increases by a factor of four.

This relationship is derived from the principle that pressure is proportional to the square of velocity, and since velocity is directly related to the rotational speed of the pump, when the speed is doubled (2 times), the pressure increases by 2 squared (2^2), which equals 4. Consequently, the correct interpretation is that doubling the rotational speed of the fire pump results in a fourfold increase in pressure.

Understanding this concept is crucial for designing and implementing effective fire suppression systems, as it helps ensure that the water pressure is adequate to deliver the required flow rates to combat a fire effectively.